# Two charges of # 8 C # and # -3 C# are positioned on a line at points # -2 # and # -4 #, respectively. What is the net force on a charge of # 3 C# at # 1 #?

Here it is:

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To find the net force on a charge of 3 C at position 1, we can use Coulomb's law:

[ F = k \frac{|q_1 q_2|}{r^2} ]

where ( F ) is the force between the charges, ( k ) is Coulomb's constant (( 8.9875 \times 10^9 ) N m²/C²), ( q_1 ) and ( q_2 ) are the magnitudes of the charges, and ( r ) is the distance between them.

First, find the force between the charge at position 1 and the charge at position -2: [ F_1 = k \frac{|q_1 q_2|}{r^2} ] [ F_1 = (8.9875 \times 10^9) \frac{|3 \times 8|}{(1-(-2))^2} ] [ F_1 = (8.9875 \times 10^9) \frac{24}{9} ] [ F_1 = 2.396 \times 10^{10} , \text{N}]

Next, find the force between the charge at position 1 and the charge at position -4: [ F_2 = k \frac{|q_1 q_2|}{r^2} ] [ F_2 = (8.9875 \times 10^9) \frac{|3 \times (-3)|}{(1-(-4))^2} ] [ F_2 = (8.9875 \times 10^9) \frac{9}{25} ] [ F_2 = 3.2364 \times 10^{9} , \text{N}]

The net force on the charge at position 1 is the vector sum of ( F_1 ) and ( F_2 ): [ F_{\text{net}} = F_1 + F_2 ] [ F_{\text{net}} = 2.396 \times 10^{10} + 3.2364 \times 10^{9} ] [ F_{\text{net}} = 2.7196 \times 10^{10} , \text{N}]

Thus, the net force on the charge of 3 C at position 1 is ( 2.7196 \times 10^{10} , \text{N}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How much power is produced if a voltage of #7 V# is applied to a circuit with a resistance of #56 Omega#?

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