Two charges of # 6 C # and # -3 C # are at points # (-2 ,4,-3 ) # and # ( -8 ,6,1 )#, respectively. Assuming that both coordinates are in meters, what is the force between the two points?

Answer 1

#F=-3*10^9 N " attractive force"#

#"distance between P_1(-2,4,-3) and P_2(-8,6,1) is given by:"# #r^2=(-8+2)^2+(6-4)^2+(1+3)^2# #r^2=36+4+16# #r²=56# #F=(k*q_1*q_2)/r^2# #F=(cancel(9)*10^9*cancel(6)*(-3))/cancel(56)# #F=-3*10^9 N " attractive force"#

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Answer 2

Carson Alexander

The force between the two charges is approximately 5.09 × 10^7 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.