Twice the difference of a number and 8 is equal to three times the sum of the number and 3. How do you find the number?

Answer 1

# 2(x-8)=3(x+3)#

#2x - 16=3x+9#

#x = -25 #

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Answer 2

Let's denote the unknown number as ( x ).

The given equation is: "Twice the difference of a number and 8 is equal to three times the sum of the number and 3."

Translating this into an equation, we get:

( 2(x - 8) = 3(x + 3) )

Now, solve for ( x ):

( 2x - 16 = 3x + 9 )

Subtract ( 2x ) from both sides:

( -16 = x + 9 )

Subtract 9 from both sides:

( x = -25 )

So, the number is -25.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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