Triangle XYZ is isosceles. The base angles, angle X and angle Y, are four times the measure of the vertex angle, angle Z. What is the measure of angle X?
Set up two equations with two unknowns
You will find X and Y = 30 degrees, Z = 120 degrees
Insert this value of X into either the first or the second equation (let's do number 2):
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Let the measure of angle Z be (x).
Since angles X and Y are each four times the measure of angle Z in an isosceles triangle:
Angle X = Angle Y = (4x).
In a triangle, the sum of all angles is (180^\circ).
So, we have the equation:
[x + 4x + 4x = 180^\circ]
Solving for (x):
[9x = 180^\circ]
[x = \frac{180^\circ}{9} = 20^\circ]
Thus, angle X is:
[4x = 4(20^\circ) = 80^\circ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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