Triangle A has an area of #4 # and two sides of lengths #12 # and #7 #. Triangle B is similar to triangle A and has a side with a length of #5 #. What are the maximum and minimum possible areas of triangle B?

Answer 1

Maximum possible area of triangle B = 2.0408
Minimum possible area of triangle B = 0.6944

#Delta s A and B # are similar.
To get the maximum area of #Delta B#, side 5 of #Delta B# should correspond to side 7 of #Delta A#.
Sides are in the ratio 5 : 7 Hence the areas will be in the ratio of #5^2 : 7^2 = 25 : 49#
Maximum Area of triangle #B =( 4 * 25) / 49= 2.0408#
Similarly to get the minimum area, side 12 of #Delta A # will correspond to side 5 of #Delta B#. Sides are in the ratio # 5 : 12# and areas #25 : 144#
Minimum area of #Delta B = (4*25)/144= 0.6944#
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Answer from HIX Tutor

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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