To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C, if the initial temperature of the glass is 20.0°C?
The objective here is to first identify the temperature change and then utilize that information to determine the sample's final temperature.
You must apply this formula.
This equation, as you can see, establishes a relationship between the mass of a substance, its specific heat, the amount of heat added or removed from the sample, and the temperature change that results.
Enter your values to obtain
The number of sig figs you have for the particular heat of glass is the answer, which is rounded to two sig figs.
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( \Delta T = \frac{q}{m \cdot c} ) ( \Delta T = \frac{5275 , \text{J}}{50.0 , \text{g} \cdot 0.50 , \text{J/g°C}} ) ( \Delta T = 211 , \text{°C} ) Final temperature: ( 20.0 , \text{°C} + 211 , \text{°C} = 231 , \text{°C} )
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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