To determine the solubility of calcium hydroxide, a chemist took 25mL of a saturated calcium hydroxide solution and found that it reacted completely with 8.13mL of #0.102mol L^-1# hydrochloric acid?
We assess the following reaction.........
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The balanced chemical equation for the reaction is:
Ca(OH)2 + 2HCl → CaCl2 + 2H2O
The moles of HCl reacted can be calculated as follows: moles HCl = (volume of HCl in L) × (concentration of HCl in mol/L) moles HCl = 0.00813 L × 0.102 mol/L = 0.0008298 mol
Since the reaction ratio is 1:2 (Ca(OH)2 to HCl), the moles of Ca(OH)2 can be determined as: moles Ca(OH)2 = 2 × moles HCl = 2 × 0.0008298 mol = 0.0016596 mol
Now, calculate the solubility of Ca(OH)2 in moles per liter: solubility = moles Ca(OH)2 / volume of solution in L solubility = 0.0016596 mol / 0.025 L = 0.066384 mol/L
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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