To determine the solubility of calcium hydroxide, a chemist took 25mL of a saturated calcium hydroxide solution and found that it reacted completely with 8.13mL of #0.102mol L^-1# hydrochloric acid?

Answer 1

We assess the following reaction.........

#Ca(OH)_2(aq) +2HCl(aq) rarr CaCl_2(aq) + 2H_2O(l)#
Now the calcium hydroxide present in solution derived from a saturated solution; and by saturation we specify an equilibrium quantity. That is the concentration of #Ca(OH)_2# was equal to the concentration as specified by the following equilibrium......
#Ca(OH)_2(s)rightleftharpoonsCa^(2+) + 2HO^-#
We had #8.13xx10^-3*Lxx0.102*mol*L^-1=8.29xx10^-4*mol# with respect to #HCl#, and thus there were HALF this molar quantity present in solution with respect to the saturated #Ca(OH)_2#; you with me.....?
This #Ca(OH)_2# was dissolved in a #25xx10^-3*L# volume, so #[Ca(OH)_2]=1/2xx(8.29xx10^-4*mol)/(25xx10^-3*L)=1.659xx10^-2*mol*L^-1#
And thus............................. #S_(Ca(OH)_2)=1.659xx10^-2*mol*L^-1xx74.09*g*mol^-1#
#=1.229*g*L^-1#.........
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Answer 2

The balanced chemical equation for the reaction is:

Ca(OH)2 + 2HCl → CaCl2 + 2H2O

The moles of HCl reacted can be calculated as follows: moles HCl = (volume of HCl in L) × (concentration of HCl in mol/L) moles HCl = 0.00813 L × 0.102 mol/L = 0.0008298 mol

Since the reaction ratio is 1:2 (Ca(OH)2 to HCl), the moles of Ca(OH)2 can be determined as: moles Ca(OH)2 = 2 × moles HCl = 2 × 0.0008298 mol = 0.0016596 mol

Now, calculate the solubility of Ca(OH)2 in moles per liter: solubility = moles Ca(OH)2 / volume of solution in L solubility = 0.0016596 mol / 0.025 L = 0.066384 mol/L

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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