Titration Problem - Calculate the concentration of 20.0 mL of an H2SO4 solution that requires 27.7 mL of a 0.100 M NaOH solution?

Answer 1

#0.06925M#

#2NaOH+H_2SO_4#--->#Na_2SO_4+2H_2O#
First calculate the number of moles (or amount) of the known solution, which in this case is the NaOH solution. The volume of NaOH is #27.7 mL#, or #0.0277L#. The concentration of NaOH is #0.100M#, or in other words, #0.100# mol/L

Amount = concentration x volume

#0.0277Lxx0.100M=0.00277# #mol#
As you can see from the reaction equation, the amount of #H2_SO_4# is half the amount of #NaOH#, as there is #2NaOH# but only #1H_2SO_4#
Amount of #H_2SO_4=0.00277/2=0.001385# #mol#

Concentration = amount/volume

#0.001385# #mol#/#0.02L=0.06925M#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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