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Three consecutive odd integers have a sum of 39. What are the numbers?

Answer 1

Ethan Adkins

The three integers are #11#, #13#, and #15#.

We shall consider the integers as #x#, #(x+2)#, and #(x+4)#. The sum of these is #39#, so we can write:

#x+(x+2)+(x+4)=39#

Simplify and make the brackets open.

#x+x+2+x+4=39#

#3x+6=39#

Subtract #6# from each side.

#3x=33#

Divide both sides by #3#.

#x=11#

Therefore: #(x+2)=13# and #(x+4)=15#

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Answer 2

Eva Abramson

Let ( x ) represent the smallest odd integer. Since the integers are consecutive, the next two odd integers are ( x + 2 ) and ( x + 4 ). Their sum is 39. So: [ x + (x + 2) + (x + 4) = 39 ] [ 3x + 6 = 39 ] [ 3x = 33 ] [ x = 11 ] The three consecutive odd integers are 11, 13, and 15.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.