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There are 15 students. 5 of them are boys and 10 of them are girls. If 5 students are chosen, what is the probability that 2 or them are boys?

Answer 1

Isaiah Anthony

#400/1001~~39.96%#.

There are #((15),(5))=(15!)/(5!10!)=3003# ways to choose 5 people out of 15.

There are #((5),(2))((10),(3))=(5!)/(2!3!)*(10!)/(3!7!)=1200# ways to choose 2 boys out of 5 and 3 girls out of 10.

Thus, the answer is #1200/3003=400/1001~~39.96%#.

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Answer 2

Jace Anderson

The probability of choosing 2 boys out of 5 students and 3 girls out of 10 students can be calculated using combinations. Then, divide the number of favorable outcomes by the total number of possible outcomes.

[ \text{Total possible outcomes} = \binom{15}{5} ]

[ \text{Favorable outcomes} = \binom{5}{2} \times \binom{10}{3} ]

[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total possible outcomes}} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.