The width of a rectangle is one-fifth as much as the length and the perimeter is 120 cm, how do you find the length and width?
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Let ( x ) represent the length of the rectangle. Since the width is one-fifth of the length, it is ( \frac{x}{5} ).
The formula for the perimeter of a rectangle is ( 2(length + width) ), so we have ( 2(x + \frac{x}{5}) = 120 ).
Solving this equation gives us ( x = 50 ).
Therefore, the length of the rectangle is 50 cm and the width is ( \frac{50}{5} = 10 ) cm.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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