# The volume V of a given mass of a gas varies directly as the temperature T and inversely as the pressure P.? If V=200 cm^3, T=40 degree and P=10 kg/cm^2, how do you find the volume when T=30 degree, P=5kg/cm^2?

To find the volume when T=30 degrees and P=5 kg/cm^2, we can use the direct variation and inverse variation formulas.

First, we need to set up the equation using the given values: V = k * (T/P)

Next, we can solve for the constant of variation (k) by substituting the initial values: 200 = k * (40/10)

Simplifying the equation: 200 = k * 4 k = 200/4 k = 50

Now that we have the value of k, we can substitute it into the equation and solve for the volume when T=30 degrees and P=5 kg/cm^2: V = 50 * (30/5) V = 50 * 6 V = 300 cm^3

Therefore, the volume when T=30 degrees and P=5 kg/cm^2 is 300 cm^3.

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The volume of gas is

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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