The volume of this box is 288 cubic cm, and the height is 4 cm. the length is triple the height, how do you find the width?
The width is
The product of a cube's length, width, and height is its volume;
Thus, if we enter the problem's information into the volume formula:
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To find the width of the box, you can use the formula for the volume of a rectangular box:
[ V = l \times w \times h ]
Given that the volume ( V = 288 ) cubic cm and the height ( h = 4 ) cm, and the length ( l ) is triple the height, we have:
[ l = 3h = 3 \times 4 = 12 \text{ cm} ]
Now, substitute the known values into the formula and solve for the width ( w ):
[ 288 = 12 \times w \times 4 ]
[ w = \frac{288}{12 \times 4} ]
[ w = \frac{288}{48} ]
[ w = 6 \text{ cm} ]
So, the width of the box is ( 6 ) cm.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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