The volume of a cylinder is doubled without changing its height. How did its radius change?

Answer 1

see explanation

Let #r and h# be the radius and the height of the cylinder.
Volume of a cylinder is #V=pir^2h# ------ (1)

If the volume is doubled without changing its height

#=> 2V=pir_2^2h# ----- (2)

Dividing Eq. (2) by Eq. (1), we get

#2=r_2^2/r^2#
#=> r_2/r=sqrt2# #=> r_2=sqrt2*r#
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Answer 2

If the volume of a cylinder is doubled without changing its height, its radius would need to be increased by a factor of (\sqrt{2}), approximately 1.414 times its original radius.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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