The vertices of triangle ABC are A(-4,0), B(2,4), and C(4,0). What is its area?
Don"t be intimidated by the points. Graph them and find your base and height
This is easy because your base is just the distance from A to A on the horizontal plane, 8. The height is defined by the vertical distance of B, 4.
Your area is 16 sq. units.
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We know from the Co-ordinate Geometry, that, if the vertices of
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To find the area of triangle ABC with vertices A(-4,0), B(2,4), and C(4,0), you can use the formula for the area of a triangle given its vertices. One common method is using the formula:
[Area = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|]
Substituting the coordinates of points A, B, and C into this formula:
[Area = \frac{1}{2} |-4(4 - 0) + 2(0 - 4) + 4(4 - 0)|]
[= \frac{1}{2} |-16 + (-8) + 16|]
[= \frac{1}{2} |-16 - 8 + 16|]
[= \frac{1}{2} |-8|]
[= \frac{1}{2} \times 8]
[= 4]
Therefore, the area of triangle ABC is 4 square units.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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