# The velocity of an object with a mass of #6 kg# is given by #v(t)= te^t-e^t #. What is the impulse applied to the object at #t= 3 #?

Impact cannot defined for an instant of time. Impact is defined for an interval of time. So the answer for this question is zero.

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To find the impulse applied to the object at ( t = 3 ), you need to calculate the change in momentum of the object over a small interval around ( t = 3 ). Impulse is defined as the change in momentum.

- Calculate the momentum of the object at ( t = 3 ) using the velocity function ( v(t) = t e^t - e^t ).
- Calculate the momentum of the object at ( t = 3 - \delta t ) (just before ( t = 3 )) using the velocity function.
- Calculate the change in momentum by subtracting the momentum at ( t = 3 - \delta t ) from the momentum at ( t = 3 ).
- The impulse is equal to the change in momentum.

After calculating the impulse, you will have the answer.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- A ball with a mass of #12# #kg# moving at #8# #ms^-1# hits a still ball with a mass of #20# #kg#. If the first ball stops moving, how fast is the second ball moving? How much kinetic energy was lost as heat in the collision?
- A ball with a mass of #1 kg# moving at #8 m/s# hits a still ball with a mass of #7 kg#. If the first ball stops moving, how fast is the second ball moving?
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