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The variables x=6 and y=3 varies directly. How do you write an equation that relates the variables and find x when y=-5?

Answer 1

Kennedy Adams

#y=1/2x,-10#

#"the initial statement is "ypropx#

#"to convert to an equation multiply by k the constant"# #"of variation"#

#rArry=kx#

#"to find k use the given condition"#

#x=6" when "y=3#

#y=kxrArrk=y/x=3/6=1/2#

#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=1/2x)color(white)(2/2)|)))#

#"when "y=-5#

#1/2x=-5rArrx=-10#

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Answer 2

Isaiah Anthony

The equation for direct variation is ( y = kx ), where ( k ) is the constant of variation. To find ( k ), substitute the given values of ( x ) and ( y ) into the equation and solve for ( k ). Then, use the value of ( k ) to find ( x ) when ( y = -5 ) by rearranging the equation to solve for ( x ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.