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The variables x=1 and y=1/2 varies directly. How do you write an equation that relates the variables and find y when x=8?

Answer 1

Kennedy Adams

#y=4#

#"the initial statement is "ypropx#

#"to convert to an equation multiply by k the constant"# #"of variation"#

#rArry=kx#

#"to find k use the given condition"#

#x=1" and "y=1/2#

#y=kxrArrk=y/x=(1/2)/1=1/2#

#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=1/2x)color(white)(2/2)|)))#

#"when "x=8#

#y=1/2xx8=4#

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Answer 2

Savannah Anderson

The equation that relates the variables is: ( y = kx ), where ( k ) is the constant of variation. Substituting the given values, ( 1/2 = k \times 1 ). Thus, ( k = 1/2 ). So, the equation becomes ( y = (1/2)x ). When ( x = 8 ), ( y = (1/2) \times 8 = 4 ). Therefore, when ( x = 8 ), ( y = 4 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.