The variables x=-0.3 and y=2.2 varies directly. How do you write an equation that relates the variables and find x when y=-5?

Answer 1

#y=-22/3x,x=15/22#

#"the initial statement is "ypropx#
#"to convert to an equation multiply by k the constant"# #"of variation"#
#rArry=kx#
#"to find k use the given condition"#
#x=-0.3" and "y=2.2#
#y=kxrArrk=y/x=(2.2xx10)/(-0.3xx10)=-22/3#
#"equation is " color(red)(bar(ul(|color(white)(2/2)color(black)(y=-(22x)/3)color(white)(2/2)|)))#
#"when "y=-5#
#x=-(3y)/22=-(3xx-5)/22=15/22#
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Answer 2

The equation relating the variables x and y when they vary directly is ( \frac{x}{y} = k ), where k is the constant of variation. To find k, substitute the given values for x and y: ( \frac{-0.3}{2.2} = k ). Then, once you have k, you can use it to find x when y = -5: ( x = ky ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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