# The tension in a 2 m length of string that whirls a 1 kg mass at 4 m/s in a horizontal circle is calculated to be 8 N. How do you alculate the tension for the following case: twice the length of string?

The tension will be

The tension and centripetal force are equal, as shown by:

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To calculate the tension for a string twice the length, you use the formula:

T = (m * v^2) / r

Where:

- T is the tension
- m is the mass (1 kg)
- v is the velocity (4 m/s)
- r is the radius of the circle (2 m)

Plug in the values and solve for T:

T = (1 kg * (4 m/s)^2) / 4 m T = (1 * 16) / 4 T = 4 N

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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