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The tension in a 2 m length of string that whirls a 1 kg mass at 4 m/s in a horizontal circle is calculated to be 8 N. How do you alculate the tension for the following case: twice the length of string?

Answer 1

Leo Abeyta

The tension will be #4"N"#

The tension and centripetal force are equal, as shown by:

#F=(mv^2)/r#

You can see that doubling #r# will therefore half the tension to #4"N"#

Verify:

#F=(1xx4^2)/4=4"N"#

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Answer 2

Carson Alexander

To calculate the tension for a string twice the length, you use the formula:

T = (m * v^2) / r

Where:

T is the tension
m is the mass (1 kg)
v is the velocity (4 m/s)
r is the radius of the circle (2 m)

Plug in the values and solve for T:

T = (1 kg * (4 m/s)^2) / 4 m T = (1 * 16) / 4 T = 4 N

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.