The sum of two numbers is 48. One number is 3 times as large as the other. What are the numbers?
I just do not understand how to solve it.
I just do not understand how to solve it.
As per question
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Let x be the smaller number and y be the larger number. Then, we have the following equations:
- x + y = 48 (since the sum of the two numbers is 48)
- y = 3x (since one number is 3 times as large as the other)
Substitute the expression for y from equation 2 into equation 1 and solve for x. Once you have found the value of x, substitute it back into equation 2 to find the value of y.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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