The sum of two numbers is 48. One number is 3 times as large as the other. What are the numbers?

I just do not understand how to solve it.

Answer 1

#12# and #36#.

Let one number be #n#. Then the other number will be #3n#.

As per question

#n+3n=48#
#=>4n=48#
#n=48/4 = 12#
Therefore, one number is #12# and the other number is
#3*12 = 36#
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Answer 2

Let x be the smaller number and y be the larger number. Then, we have the following equations:

  1. x + y = 48 (since the sum of the two numbers is 48)
  2. y = 3x (since one number is 3 times as large as the other)

Substitute the expression for y from equation 2 into equation 1 and solve for x. Once you have found the value of x, substitute it back into equation 2 to find the value of y.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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