The sum of two consecutive integers is 71. What are the integers?

Answer 1

The integers are 35 and 36

Let #n# = the 1st integer Therefore the 2nd integer is #(n+1)#
We are told that the sum of these two integers is #71# Hence: #n + (n+1) = 71#
#2n + 1 = 71#
#n = (71-1)/2#
#n = 35 -> (n+1) =36#
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Answer 2

Let the first integer be (x), and the next consecutive integer be (x + 1). Since they are consecutive integers, their sum is (x + (x + 1) = 2x + 1). Given that the sum is 71, we can set up the equation: [2x + 1 = 71] [2x = 71 - 1] [2x = 70] [x = \frac{70}{2}] [x = 35] So, the first integer is 35, and the next consecutive integer is (35 + 1 = 36).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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