The sum of two consecutive integers is 71. What are the integers?
The integers are 35 and 36
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Let the first integer be (x), and the next consecutive integer be (x + 1). Since they are consecutive integers, their sum is (x + (x + 1) = 2x + 1). Given that the sum is 71, we can set up the equation: [2x + 1 = 71] [2x = 71 - 1] [2x = 70] [x = \frac{70}{2}] [x = 35] So, the first integer is 35, and the next consecutive integer is (35 + 1 = 36).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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