The sum of three consecutive odd integers is 279, what are the integers?

Answer 1
Suppose the integers are #n#, #n + 2# and #n+4#

We have:

#279 = n + (n+2) + (n+4) = 3n+6#
Subtract #6# from both sides to get:
#3n = 273#
Divide both sides by #3# to get:
#n = 91#

The three numbers are thus:

#91, 93, 95#
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Answer 2

Let ( x ) be the first odd integer. Then the next two consecutive odd integers are ( x + 2 ) and ( x + 4 ). According to the problem, their sum is 279. So, the equation becomes ( x + (x + 2) + (x + 4) = 279 ). Solving this equation, we get ( x = 91 ). Therefore, the three consecutive odd integers are 91, 93, and 95.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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