The sum of three consecutive odd integers is 231, how do you find the integers?

Answer 1

The integers are #75, 77 # and # 79#

Three consecutive odd integers can be denoted as: #(x) , (x+2)# and# (x+4)#
The sum #=231#

So,

#x + x+2 + x+4 = 231#
#3x+6 = 231#
#3x = 231-6#
#3x = 225#
#x=225/3#
#color(blue)(x=75#
The integers are as follows: #x; color(blue)(75#
#x+2; color(blue)(77# and
#x+4;color(blue)( 79#
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Answer 2

Numbers are #75#, #77# and #79#.

Let the three odd numbers be #2x-1#, #2x+1# and #2x+3#. (These numbers have been chosen as these will always be three consecutive odd number for any natural number #x#).
As sum of these numbers is #231#
#2x-1+2x+1+2x+3=231# or
#6x+3=231# or #6x=231-3=228#
Hence #6x=228# or #x=228/6=38# and numbers are
#2xx38-1#, #2xx38+1# and #2xx38+3#
or #75#, #77# and #79#.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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