The sum of three consecutive integers is 87, what are the integers?

Answer 1

#28, 29, 30#

I'll use #x# to represent the smallest integer (consecutive integers come right after one another, so #x+1# and #x+2# would be the next two integers):
#x+x+1+x+2=87#
#3x+3=87#
#3x=84#
#x=28#
#x+1=29#
#x+2=30#
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Answer 2

Let ( n ) represent the first integer. Then the three consecutive integers are ( n, n+1, ) and ( n+2 ). Their sum is given as 87. Thus,

[ n + (n+1) + (n+2) = 87 ]

Combining like terms, we have:

[ 3n + 3 = 87 ]

Subtracting 3 from both sides:

[ 3n = 84 ]

Finally, dividing both sides by 3:

[ n = 28 ]

Therefore, the three consecutive integers are 28, 29, and 30.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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