The sum of three consecutive integers is -75. What are the integers?

Answer 1

The numbers are #-26, -25# and #-24#.

Let the numbers #a, a+1 and a + 2#
#a + (a + 1) + (a + 2) = -75#
#3a + 3 = -75#
#3a = -78#
#a = -78/3#
#a = -26 => #
#a + 1 = -26 + 1 = -25#
#a + 2 = -26 + 2 = -24#

The numbers are -26, -25 and -24.

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Answer 2

Let the three consecutive integers be x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. Given that the sum is -75, we can set up the equation: 3x + 3 = -75. Solving for x, we find x = -26. So the integers are -26, -25, and -24.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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