The sum of three consecutive integers is 53 more than the least of the integers, how do you find the integers?

Answer 1

Hazel Anglin

The integers are: #25,26,27#

If you assume, that the smallest number is #x# then the conditions in the task lead to equation:

#x+x+1+x+2=53+x# #3x+3=53+x# #2x=50# #x=25#

So you get the numbers: #25,26,27#

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Answer 2

Isaiah Anthony

Let ( n ) represent the least of the integers. Then the next two consecutive integers are ( n + 1 ) and ( n + 2 ). According to the problem, their sum is 53 more than ( n ). Therefore, the equation is ( n + (n + 1) + (n + 2) = n + 53 ). Solving for ( n ) gives ( n = 18 ). So the three consecutive integers are 18, 19, and 20.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.