The sum of three consecutive integers is 258. How do you find the three integers?
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Let ( x ) represent the first integer. Then the next two consecutive integers are ( x + 1 ) and ( x + 2 ). The sum of the three consecutive integers is ( x + (x + 1) + (x + 2) = 3x + 3 ). Given that the sum is 258, we set up the equation ( 3x + 3 = 258 ) and solve for ( x ). Subtract 3 from both sides: ( 3x = 255 ). Divide both sides by 3: ( x = 85 ). So the three consecutive integers are 85, 86, and 87.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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