The sum of three consecutive integers is 216. What is the largest of the three integers?

Answer 1

Julia Adams

The largest number is 73

Let the first integer be #n#

Then #n+(n+1)+(n+2)=216#

#=>3n +3=216#

Deduct three from each side.

#3n=213#

Split each side in half.

#n=71#

So the largest numbr #->n+2=71+2=73#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Jameson Allen

Let's denote the smallest of the three consecutive integers as ( x ). Then, the next two consecutive integers would be ( x + 1 ) and ( x + 2 ). According to the given information:

[ x + (x + 1) + (x + 2) = 216 ]

Solving this equation yields:

[ 3x + 3 = 216 ]

[ 3x = 213 ]

[ x = 71 ]

So, the three consecutive integers are 71, 72, and 73. Therefore, the largest of the three integers is ( 73 ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.