The sum of three consecutive integers is 162, what are the integers?

Answer 1

The integers will be: #53,54,55#.

Call your integers: #n, n+1, n+2# so you get: #n+(n+1)+(n+2)=162# #3n+3=162# #3n=159# so: #n=53# The integers will then be: #53,54,55#.
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Answer 2

Let's represent the three consecutive integers as x, x + 1, and x + 2. According to the problem, the sum of these integers is 162. So, we can write the equation: x + (x + 1) + (x + 2) = 162. Solving this equation yields x = 53. Therefore, the consecutive integers are 53, 54, and 55.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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