The sum of three consecutive even integers is 114, what are the integers?

Answer 1

#36, 38, 40#

Let #x# be the smallest of these three numbers. The next even number is, obviously, #x+2#. The third one is #x+4#.
So, #x+(x+2)+(x+4)=114# or #3x+6=114# From this equation we derive: #x=36# from which follows: #x+2=38# #x+4=40#
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Answer 2

Let's call the first even integer x. Since the integers are consecutive even integers, the second one would be x + 2, and the third one would be x + 4.

According to the given condition, the sum of these three consecutive even integers is 114.

Therefore, the equation to solve is:

x + (x + 2) + (x + 4) = 114

Solve for x:

3x + 6 = 114 3x = 108 x = 36

So, the first even integer is 36, the second one is 38, and the third one is 40.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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