The sum of the measures of the interior angles of a convex polygon is 540. How do you classify the polygon by the number of sides?

Answer 1

Polygon is a pentagon i.e. #5# sides.

If #n# are number of sides of a convex polygon, sum of its interior angles is #(n-2)xx180^@#
As in given case sum of interior angles is #540^@#, we have
#(n-2)xx180^@=540^@#
or #n-2=540/180=3#
and #n=3+2=5#

Hence, polygon is a pentagon.

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Answer 2

To classify the polygon by the number of sides, we can use the formula for the sum of the interior angles of a polygon: ( (n - 2) \times 180^\circ ), where ( n ) represents the number of sides of the polygon.

Given that the sum of the measures of the interior angles of the convex polygon is 540 degrees, we can set up the equation:

[ (n - 2) \times 180^\circ = 540^\circ ]

Solving for ( n ):

[ (n - 2) \times 180^\circ = 540^\circ ] [ n - 2 = \frac{540^\circ}{180^\circ} ] [ n - 2 = 3 ] [ n = 3 + 2 ] [ n = 5 ]

So, the polygon has 5 sides, and it is classified as a pentagon.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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