# The sum of eight consecutive (one after the other) numbers is 88. What are the numbers?

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Let's represent the smallest of the eight consecutive numbers as ( x ). Then the next seven consecutive numbers would be ( x + 1 ), ( x + 2 ), ( x + 3 ), ( x + 4 ), ( x + 5 ), ( x + 6 ), and ( x + 7 ).

The sum of these eight consecutive numbers is given as 88:

[ x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) + (x + 7) = 88 ]

Solve this equation for ( x ) to find the smallest number in the sequence. Then, you can determine the other consecutive numbers by adding the corresponding values of ( x ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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