# The sum of 6 consecutive integers is 393. What is the third number In this sequence?

65

The sum of these six integers is 393 so we can write:

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Let the third integer in the sequence be ( x ). The sum of the six consecutive integers can be represented as: ( x-2 + x-1 + x + x+1 + x+2 + x+3 = 393 ). Solving this equation yields ( x = 65 ). Therefore, the third number in the sequence is ( 65 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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