The successive ionization energies of an element A are as follows?

Question

If the IE(1) and IE(3) values are #(27 ext{KJ})/ ext{mole}# and #(51 ext{KJ})/ ext{mole}# respectively , then the value of IE(2) is in #( ext{KJ})/ ext{mole}#?

A) #21#
B)#33#
C)#59#
D)#63#

Natalie Anton · Accepted Answer

#IE_1 < IE_2 < IE_3#
OPTION B

clearly the energy required to knock out second electron will be less than the energy required to knock out the third electron(due to increasing effective nuclear charge with each electron gone) . Hence #IE_2#< 51 KJ/mole. And similarly more energy is required to knock out the second electron than the energy required to knock out the outermost valence electron. Hence #IE_2#< 27 KJ/mole The only option which matches both the criteria is Option B **

Cameron Andrews · Answer

Would we not expect it to be #B#...?

On the basis of simple electrostatics (forgot for the moment about energy levels), would we not expect the SECOND oxidation of an element to be GREATER than the first, and LESS than the THIRD...?

#M(g) + Delta_1 rarr M^(+)(g)+e^(-)#

#M(g)^+ + Delta_2 rarr M^(2+)(g)+e^(-)#

And likewise...

#M(g)^(2+) + Delta_3 rarr M^(3+)(g)+e^(-)#

And as chemists, as physical scientists, we are obliged to consider the data... Consider successive ionizations represented by the graph...

Do these data support or detract from our argument?

Xavier Avery · Answer

undefined To provide an accurate answer, I would need the specific values of the successive ionization energies of the element A. These values are typically given in kilojoules per mole (kJ/mol) or electron volts (eV). Once I have these values, I can help analyze the trends and patterns in the successive ionization energies of the element A. Without the specific values, it's not possible to provide a comprehensive answer. Please provide the values, and I'll be happy to assist you further.

The successive ionization energies of an element A are as follows?

If the IE(1) and IE(3) values are #(27\text{KJ})/\text{mole}# and #(51\text{KJ})/\text{mole}# respectively , then the value of IE(2) is in #(\text{KJ})/\text{mole}#? A) #21# B)#33# C)#59# D)#63#

If the IE(1) and IE(3) values are #(27\text{KJ})/\text{mole}# and #(51\text{KJ})/\text{mole}# respectively , then the value of IE(2) is in #(\text{KJ})/\text{mole}#?

A) #21#
B)#33#
C)#59#
D)#63#