The student tickets cost $6.00 less than the general admission tickets. The total amount of money collected for student tickets was $1800 and for general admission tickets, $3000. What was the price of a general admission ticket?

$15
$9
$12
$6

Answer 1

From what I can see, this problem doesn't have any unique solution.

Call the cost of an adult ticket #x# and the cost of a student ticket #y#.
#y = x - 6#
Now, we let the number of tickets sold be #a# for the students and #b# for the adults.
#ay = 1800#
#bx= 3000#
We are left with a system of #3# equations with #4# variables which has no unique solution.

Perhaps the question is missing a piece of information??. Please let me know.

Hopefully this helps!

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Answer 2

Let's denote the price of a general admission ticket as ( x ) dollars.

Since the student tickets cost $6.00 less than the general admission tickets, the price of a student ticket would be ( x - 6 ) dollars.

If the total amount collected for student tickets was 1800,thenthenumberofstudentticketssoldcanbefoundbydividing1800, then the number of student tickets sold can be found by dividing 1800 by the price of a student ticket: ( \frac{1800}{x - 6} ).

Similarly, if the total amount collected for general admission tickets was 3000,thenthenumberofgeneraladmissionticketssoldcanbefoundbydividing3000, then the number of general admission tickets sold can be found by dividing 3000 by the price of a general admission ticket: ( \frac{3000}{x} ).

Since the total number of tickets sold is the sum of the student tickets and general admission tickets, we can set up the following equation:

[ \frac{1800}{x - 6} + \frac{3000}{x} = \text{Total number of tickets} ]

Since we're given the total amount collected for each type of ticket, we can simplify the equation:

[ \frac{1800}{x - 6} + \frac{3000}{x} = \frac{1800}{x - 6} + \frac{3000}{x} = \text{Total number of tickets} = \text{Total number of student tickets} + \text{Total number of general admission tickets} ]

Now, we can solve for ( x ), the price of a general admission ticket.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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