The student tickets cost $6.00 less than the general admission tickets. The total amount of money collected for student tickets was $1800 and for general admission tickets, $3000. What was the price of a general admission ticket?
$15
$9
$12
$6
$15
$9
$12
$6
From what I can see, this problem doesn't have any unique solution.
Perhaps the question is missing a piece of information??. Please let me know.
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Let's denote the price of a general admission ticket as ( x ) dollars.
Since the student tickets cost $6.00 less than the general admission tickets, the price of a student ticket would be ( x - 6 ) dollars.
If the total amount collected for student tickets was 1800 by the price of a student ticket: ( \frac{1800}{x - 6} ).
Similarly, if the total amount collected for general admission tickets was 3000 by the price of a general admission ticket: ( \frac{3000}{x} ).
Since the total number of tickets sold is the sum of the student tickets and general admission tickets, we can set up the following equation:
[ \frac{1800}{x - 6} + \frac{3000}{x} = \text{Total number of tickets} ]
Since we're given the total amount collected for each type of ticket, we can simplify the equation:
[ \frac{1800}{x - 6} + \frac{3000}{x} = \frac{1800}{x - 6} + \frac{3000}{x} = \text{Total number of tickets} = \text{Total number of student tickets} + \text{Total number of general admission tickets} ]
Now, we can solve for ( x ), the price of a general admission ticket.
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