The specific heat of steel is 420 J/(kg°C). How much energy is required to heat 1 kg of steel by 20 °C?

Answer 1

#"8400 J"#

The specific heat of a substance tells you how much heat is required in order to heat one unit of mass, usually #"1 g"#, of that substance by #1^@"C"#.
In this case, the specific heat of steel uses #"1 kg"# as the unit of mass, which means that the value given to you tells you how much heat is required in order to heat #"1 kg"# of steel by #1^@"C"#.

Since you have

#c = "420 J kg"^(-1)""^@"C"^(-1)#
you can say that you need #"420 J"# of heat in order to increase the temperature of #"1 kg"# of steel by #1^@"C"#.
This means that in order to increase the temperature of a given mass of steel by #20^@"C"#, you'd need
#20 color(red)(cancel(color(black)(""^@"C"))) * "420 J"/("1 kg" color(red)(cancel(color(black)(""^@"C")))) = "8400 J kg"^(-1)#
For #"1 kg"#, this gives you
#1 color(red)(cancel(color(black)("kg"))) * "8400 J"/(1color(red)(cancel(color(black)("kg")))) = color(darkgreen)(ul(color(black)("8400 J")))#

I'll leave the answer rounded to two sig figs.

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Answer 2

The energy required to heat 1 kg of steel by 20°C is 8,400 J.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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