The solubility of lead (II) Iodate, #Pb(IO_3)_2#, is 0.76 g/L at 25*C. How do you calculate the Value of Ksp at this same temperature?
Lead iodate is thus quite an insoluble beast.
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[ \text{K}_{\text{sp}} = [\text{Pb}^{2+}][\text{IO}_3^-]^2 ]
Given the solubility of lead (II) iodate ((\text{Pb(IO}_3)_2)) is 0.76 g/L, convert this to moles per liter. Use the stoichiometric coefficients to determine the concentration of lead ions ((\text{Pb}^{2+})) and iodate ions ((\text{IO}_3^-)). Substitute these values into the Ksp expression to find the Ksp value at 25°C.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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