The region is bounded by the given curves #y=x, y=4-x, 0<=x<=2# is rotated about the x-axis, how do you find the volume of the two solids of revolution?
See below.
I am reading this as the volume of the shaded area A rotated around the x axis, and the volume of shaded area B rotated around the x axis. First we find the volume of B, then we find the volume of A+B and subtract volume B from this to find the volume A
Volume of B
Volume of A + B Volume of A = (A + B) - B. So: Volume of A = Volume of B = Revolution of A:
Revolution of B:
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To find the volume of the two solids of revolution, you first need to find the points of intersection of the curves y = x and y = 4 - x. These points are (2, 2) and (0, 4).
For the first solid, the outer curve is y = 4 - x and the inner curve is y = x.
For the second solid, the outer curve is y = x and the inner curve is y = 4 - x.
Using the disk method, the volume of each solid can be calculated by integrating the area of the cross-sections perpendicular to the x-axis.
For the first solid: [V_1 = \pi \int_0^2 (4-x)^2 - x^2 ,dx]
For the second solid: [V_2 = \pi \int_0^2 x^2 - (4-x)^2 ,dx]
Integrate each expression over the given interval to find the volume of each solid.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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