The ratio of Maya's money to Sophia is 3 : 7. Sophia has $64 more than Maya. If Sophia gives 14 of her money to Maya, what will be the new ratio?

Answer 1

#31/49#

# 3 xx x + 64 = 7 xx x#

Maya's money is equal to Sophia's money if you add 64 to it.

as the ratio is 3: 7 whatever amount of money ( x) is in the ratio of the # 3 xx x # and # 7 xx x# so take the equation and solve for x

3x plus 64 equals 7x. Take 64 out of both sides of the equation.

3x + 64-64 = 7 x - 64, which results in

3x is equal to 7 x -64. Take 7x out of both sides of the equation.

3 - 7 x = 7 - 7 x - 64, which results in

Divide both sides by -4 to get -4x = -64.

# -4 xx x/-4 = -64/-4 # this gives
# 3 xx 16 = 48# for Maya

7 xx 16 = 112 for Sophia

Take 14 from Sophia and add it to Maya.

For Maya, 48 + 14 = 62; for Sophia, 112 - 14 = 98

The new ratio is # 62/98# divide by two (2) gives

For the revised ratio, 31: 49.

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Answer 2

#31 : 49#

There is a difference of 4 parts between 3 parts and 7 parts. The amounts differ by $64.

Four times 64 is 16. One part is 16.

Thus, the sums of money are

M: S3: 748: 112

Sophia gives $14 to Maya:

62.2: 98 31.6: 49

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Answer 3

#"Maya : Sophia "->" "31:49#

You are comparing total counts when you use a ratio.

Because of the 3:7 ratio, the total count is 3 + 7 = 10.

Using fractional notation to display the ratio:

#("Maya")/("Sophia") -> 3/7#

The difference in the amount of money at the start is $64. So

7 parts - 3 parts = 4 parts and the difference is $64

So 1 part is #($64)/4 = $16#
#("Maya")/("Sophia")" " ->" " 3/7" " ->" " (3xx$16)/(7xx$16) = ($48)/($112)#
'............................................................. Check: #10" units"xx$16= 160#
#$48+$112 = $160# '.......................................................

Sophia gives $14

#("Maya")/("Sophia")" "->" "($48+$14)/($112-$14)" "->" "($62)/($98)#
#("Maya")/("Sophia")" "->" "31/49#
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Answer 4

To find the new ratio after Sophia gives 14 of her money to Maya, first, calculate the amount of money Sophia initially has and the amount Maya initially has based on the given ratio.

Let's denote the amount of money Maya has as (3x) dollars and the amount Sophia has as (7x) dollars.

Given that Sophia has $64 more than Maya, we can set up the equation:

[7x = 3x + 64]

Solve for (x), which represents the difference in their money amounts.

Once you find the value of (x), determine the initial amounts of money each has, and then calculate how much Sophia will have left after giving 14 dollars to Maya.

Finally, find the new ratio by comparing the new amounts of money each has.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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