# The pressure of a sample of dry air is held constant at 2.25 atm while the temperature is decreased rom 100 °C to 7 °C. The original volume of the sample is 43 L. What is the final volume of the sample?

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To find the final volume of the sample, you can use the combined gas law formula:

(P_1 \cdot V_1 / T_1 = P_2 \cdot V_2 / T_2)

Given: (P_1 = 2.25 , \text{atm}) (V_1 = 43 , \text{L}) (T_1 = 100 + 273.15 = 373.15 , \text{K}) (P_2 = 2.25 , \text{atm}) (T_2 = 7 + 273.15 = 280.15 , \text{K})

Substitute the values and solve for (V_2):

(2.25 \cdot 43 / 373.15 = 2.25 \cdot V_2 / 280.15)

(V_2 = (2.25 \cdot 43 \cdot 280.15) / (373.15 \cdot 2.25) = 32.30 , \text{L})

The final volume of the sample is approximately (32.30 , \text{L}).

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