# The pressure of 250 kPa acting on 15 cubic meters of gas at a temperature of 100 K is increased to 500 kPa and the volume is increased to 30 cubic meters. What is the temperature of the gas at this new pressure and volume?

The final temperature will be 400 K.

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Use the ideal gas law: (PV = nRT). Rearrange it to find the final temperature ((T_2)):

[T_2 = \frac{P_2 \cdot V_2 \cdot T_1}{P_1 \cdot V_1}]

Substitute values:

[T_2 = \frac{(500 , \text{kPa}) \cdot (30 , \text{m}^3) \cdot (100 , \text{K})}{(250 , \text{kPa}) \cdot (15 , \text{m}^3)}]

Calculate (T_2).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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