The pressure exerted on 800mL of a gas is decreased from 300 kPa to 198 kPa. What is the new volume of the gas if the temp remains constant?

Answer 1

#V_2=1200*mL........#

At constant temperature, #PV=k#, for a fixed amount (mass) of gas. This is old Boyle's Law:
Since #PV=k#, #P_1V_1=P_2V_2#
#V_2=(P_1V_1)/P_2=(300*kPaxx800*mL)/(198*kPa)=??*mL#. A good question in that you don't have to use a calculator.........
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Answer 2

To find the new volume of the gas, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature is constant. The formula is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively. Rearranging the formula to solve for V2, we get V2 = (P1 * V1) / P2. Plugging in the given values, we have V2 = (300 kPa * 800 mL) / 198 kPa. Solving for V2, we get V2 ≈ 1212.12 mL. Therefore, the new volume of the gas is approximately 1212.12 mL.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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