The pressure acting on 60 cubic meters of gas is raised from 236 kPa to 354 kPa. The temperature is kept constant. What new volume does the gas occupy?

Question

Avery Adams · Accepted Answer

#40m^3#

According to Boyle's Law, if the temperature doesn't change, the volume of an enclosed gas is inversely proportional to the pressure applied to it.

#therefore P_1V_1=P_2V_2#

#therefore V_2=(P_1V_1)/P_2#

#=(236xx60)/354#

#=40m^3#

Jose Ayala · Answer

undefined Using Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant:

P1 * V1 = P2 * V2

Where:
P1 = Initial pressure = 236 kPa
V1 = Initial volume = 60 cubic meters
P2 = Final pressure = 354 kPa
V2 = Final volume (to be calculated)

Rearranging the equation to solve for V2:

V2 = (P1 * V1) / P2

Substituting the given values:

V2 = (236 kPa * 60 cubic meters) / 354 kPa
V2 ≈ 40 cubic meters

So, the new volume the gas occupies is approximately 40 cubic meters.