The point-slope form of the equation of the line that passes through #(-5,-1)# and #(10, -7)# is #y + 7 =-2/5(x-10).# What is the standard form of the equation for this line?

Answer 1

#2/5x + y = -3#

The format of standard form for an equation of a line is #Ax+By = C#.
The equation that we have, #y+7 = -2/5(x-10)# is currently in point-slope form.
The first thing to do is to distribute the #-2/5(x-10)#: #y + 7 = -2/5(x-10)#
#y + 7 = -2/5x+ 4#
Now let's subtract #4# from both sides of the equation: #y + 3 = -2/5x#
Since the equation needs to be #Ax+By = C#, let's move #3# to the other side of the equation and #-2/5x# to the other side of the equation: #2/5x + y = -3#

This equation is now in standard form.

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Answer 2

#2x-5y=15#

#"the equation of a line in standard form is."#
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"rearrange "y+7=-2/5(x-10)" into this form"#
#y+7=2/5x+4larrcolor(blue)"distributing"#
#rArry=2/5x-3larrcolor(blue)"collecting like terms"#
#"multiply through by 5"#
#rArr5y=2x-15#
#rArr2x-5y=15larrcolor(red)"in standard form"#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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