# The perimeter of a square is 12 cm greater than that of another square. Its area exceeds the area of the other square by 39 sq cm. How do you find the perimeter of each square?

32cm and 20cm

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Let's denote the side length of the first square as x and the side length of the second square as y.

Given that the perimeter of the first square is 12 cm greater than the perimeter of the second square, we can write:

4x = 4y + 12

Given that the area of the first square exceeds the area of the second square by 39 sq cm, we can write:

x^2 = y^2 + 39

Now, solve these two equations simultaneously to find the values of x and y. Once you have the side lengths, you can find the perimeter of each square by multiplying the side length by 4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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