The perimeter of a basketball court is 114 meters and the length is 6 meters longer than twice the width. What are the length and width?
Width
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Let's denote the width of the basketball court as ( w ) meters. According to the problem, the length is 6 meters longer than twice the width, which can be represented as ( 2w + 6 ) meters.
Given that the perimeter of the basketball court is 114 meters, we can set up the equation for the perimeter:
[ \text{Perimeter} = 2(\text{Length}) + 2(\text{Width}) ]
Substituting the expressions for length and width:
[ 114 = 2(2w + 6) + 2w ]
Simplify and solve for ( w ):
[ 114 = 4w + 12 + 2w ]
[ 114 = 6w + 12 ]
[ 6w = 114 - 12 ]
[ 6w = 102 ]
[ w = \frac{102}{6} ]
[ w = 17 ]
Now, we can find the length using ( 2w + 6 ):
[ \text{Length} = 2(17) + 6 ]
[ \text{Length} = 34 + 6 ]
[ \text{Length} = 40 ]
Therefore, the width of the basketball court is 17 meters, and the length is 40 meters.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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