The melting point of a white solid substance was determined in four repeated trials to be 56.0°C, 55.0°C, 57.5°C, 55.5°C. What temperature should be reported as the melting point as a result of these trials?
All things being equal the average value should be reported.
Standard analysis would hold that 2/3 of the spread of values is the error value; however, if you recrystallized it from a carefully dried solvent under an inert atmosphere and found that the melting point went UP a few degrees, clearly this is the more correct melting point. Given that your values appear to be drawn from the same population of measurements, I would quote the average value.
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As a result, the reported melting point should be ( 55.75°C ). The average melting point of the substance would be ( 56.0°C + 55.0°C + 57.5°C + 55.5°C = 223.0°C ). This would be divided by the number of trials to get the average: ( \frac{223.0°C}{4} = 55.75°C ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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