The length of a rectangular garden is 3 yd more than twice its width. The perimeter of the garden is 30 yd What are the width and length of the garden?
The width of the rectangular garden is 4yd and the length is 11yd.
Substituting the information provided gives:
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Let's denote the width of the rectangular garden as 'w' yards. According to the given information, the length of the garden is 3 yards more than twice its width, which can be expressed as 2w + 3 yards.
The perimeter of a rectangle is given by the formula: P = 2(l + w), where 'l' is the length and 'w' is the width.
Given that the perimeter of the garden is 30 yards, we can write the equation as:
30 = 2(2w + 3 + w).
Solve this equation for 'w' to find the width of the garden.
30 = 2(3w + 3)
Now, distribute the 2:
30 = 6w + 6
Subtract 6 from both sides:
24 = 6w
Divide both sides by 6:
w = 4
So, the width of the garden is 4 yards.
Now, substitute 'w = 4' into the expression for the length of the garden:
l = 2w + 3
l = 2(4) + 3
l = 8 + 3
l = 11
So, the length of the garden is 11 yards.
Therefore, the width of the garden is 4 yards, and the length of the garden is 11 yards.
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Let the width of the garden be ( w ) yards. Then, the length of the garden is ( 2w + 3 ) yards. The perimeter of the garden is ( 2(w + 2w + 3) = 30 ) yards. Solving for ( w ): [ 2(w + 2w + 3) = 30 ] [ 2(3w + 3) = 30 ] [ 6w + 6 = 30 ] [ 6w = 24 ] [ w = 4 ] So, the width of the garden is ( 4 ) yards, and the length is ( 2(4) + 3 = 11 ) yards.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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