The length of a rectangle is 5 less than twice its width. The perimeter is 26 meters. How do you find the dimensions of the rectangle?

Question

Savannah Anderson · Accepted Answer

Width is 6 meters and length is 7 meters.

Let width be #x# and length be #y#. We know that the length of the rectangle is 5 less than twice its width. This can be written as: #y=2x-5# In addition, we are aware that the rectangle has a perimeter of 26 meters, which is the total of its two widths and two lengths. #P=2x+2y# #26=2(x+y)# #x+y=13# We now have two equations which we can solve simultaneously. Substitute #y=2x-5# into the second equation: #x+y=13# #x+(2x-5)=13# #3x=18# #x=6# Now that we have a value for #x# (width), we can sub this value into the first equation to get #y# (length). #y=2(6)-5# #y=7# I hope this helps:) You can solve simultaneous equations using different techniques.

Eli Assouline · Answer

undefined Width: 6 meters, Length: 7 meters